Solution:
In a circle with center O and radius 3cm and p is at a distance of 5cm.
That is OT = 3 cm, OP = 5 cm
OT is the radius of the circle
OT ⊥ PT
Now in right ∆ OTP, by Pythagoras axiom,
OP2 = OT2 + PT2
(5)2 = (3)2 + PT2
PT2 = (5)2 – (3)2 = 25 – 9 = 16 = (4)2
PT = 4 cm.