Find the rate of change or the area of a circle with respect to its radius \mathrm{r} when \mathrm{r}=5 \mathrm{~cm}.
Find the rate of change or the area of a circle with respect to its radius \mathrm{r} when \mathrm{r}=5 \mathrm{~cm}.

Area of circle =\pi r^{2}

    \[\mathrm{A}=\pi \mathrm{r}^{2}\]

differentiating with respect to \mathrm{r} we get

    \[\frac{\mathrm{dA}}{\mathrm{dr}}=2 \pi \mathrm{r}\left(\frac{\mathrm{dr}}{\mathrm{dr}}\right)\]

    \[\frac{\mathrm{dA}}{\mathrm{dr}}=2 \pi \mathrm{r}\]

    \[\frac{\mathrm{dA}}{\mathrm{dr}}=2 \times 5 \times \pi\]

    \[\frac{\mathrm{dA}}{\mathrm{dr}}=10 \pi \frac{\mathrm{cm}^{2}}{\mathrm{~cm}}\]

This is rate of change of area of circle with respect to radius 5 \mathrm{~cm}