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Home » Find the ratio in which the line segment joining A (1, – 5) and B (- 4, 5) is divided by the x-axis. Also find the coordinates of the point of division.
Find the ratio in which the line segment joining A (1, – 5) and B (- 4, 5) is divided by the x-axis. Also find the coordinates of the point of division.
CBSE | Class 10 | Coordinate Geometry | Maths | NCERT
Find the ratio in which the line segment joining A (1, – 5) and B (- 4, 5) is divided by the x-axis. Also find the coordinates of the point of division.

Solution:

Let k : 1 be the ratio of the line segment connecting A (1, – 5) and B ( – 4, 5) divided by the x-axis. As a result, the coordinates of the division point, P(x, y), are ((-4k+1)/(k+1), (5k-5)/(k+1)).

Or P(x, y)=\frac{-4k+1}{k+1},\frac{5k-5}{k+1}

We know that any point on the x-axis has a y-coordinate of 0.

( 5k – 5)/(k + 1) = 0

5k = 5

or k = 1

As a result, the x-axis divides the line segment in a 1:1 ratio.

Find the coordinates of the division point now:

P (x, y) = ((-4(1)+1)/(1+1) , (5(1)-5)/(1+1)) = (-3/2 , 0)

i

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