From each corner of a square of side 4 cm a quadrant of a circle of radius 1 cm is cut and also a circle of diameter 2 cm is cut as shown in Fig. 12.23. Find the area of the remaining portion of the square.
From each corner of a square of side 4 cm a quadrant of a circle of radius 1 cm is cut and also a circle of diameter 2 cm is cut as shown in Fig. 12.23. Find the area of the remaining portion of the square.

Solution:

4 cm = side of the square

1 cm = radius of the circle

Four quadrants of a circle are cut from the corner, and one radius circle is cut from the middle.

The area of square (side)2 = 4= 16 cm2

The area of the quadrant = (πR2)/4 cm2 = (22/7)×(12)/4 = 11/14 cm2

Therefore, the total area of the 4 quadrants = 4 ×(11/14) cm2 = 22/7 cm2

The area of circle = πRcm2 = (22/7×12) = 22/7 cm2

Area of square – (Area of the 4 quadrants + Area of the circle) = Area of the shaded region

= 16 cm2-(22/7) cm2+(22/7) cm2

= 68/7 cm2