Given the standard electrode potentials,
K+/K = –2.93V

Ag+/Ag = 0.80V,

Hg2+/Hg = 0.79V

Mg2+/Mg = –2.37 V,

Cr3+/Cr = – 0.74V
Given the standard electrode potentials,
K+/K = –2.93V

Ag+/Ag = 0.80V,

Hg2+/Hg = 0.79V

Mg2+/Mg = –2.37 V,

Cr3+/Cr = – 0.74V

Solution: As the reduction potential is reduced, the reducing power increases proportionally. The following are the standard electrode potentials in ascending order (increasing order): K+/K < Mg2+/Mg < Cr3+/Cr < Hg2+/Hg < Ag+/Ag

Therefore, in the order of reducing power, we can arrange the given metals as Ag< Hg < Cr < Mg < K