How much electricity is required in coulomb for the oxidation of
(i) 1 mol of H_{2} O to O_{2} ?
(ii) 1 mol of FeO to Fe_{2} O_{3} ?
How much electricity is required in coulomb for the oxidation of
(i) 1 mol of H_{2} O to O_{2} ?
(ii) 1 mol of FeO to Fe_{2} O_{3} ?

Solution:

(i) From given data, we write the equations that can be derived

    \[H_{2} O \rightarrow H_{2}+\frac{1}{2} O_{2}\]

We can say that :

    \[O^{2-} \rightarrow \frac{1}{2} O_{2}+2 e^{-}\]


Electricity required for the oxidation of 1 mol of H_{2}O to O_{2} =2 F

    \[\begin{aligned}&=2 \times 96487 C \&=192974 C\end{aligned}\]


(ii) From given data, we write the equations that can be derived

    \[Fe ^{2+} \rightarrow Fe ^{3+}+e^{-}\]


Electricity required for the oxidation of 1 mol of FeO to Fe_{2}O_{3}=1 F =96487 C