Answer:
Given in the question,
I = 5A
R = 100 ohm
T = 2 hours
It is known to us that,
Energy consumed = P × T = I2RT
Substituting the values,
Energy consumed = 5kWh
1kWh = 3.6 × 106J
Therefore we got,
5kWh = 5 ×3.6 × 106J = 18 × 106J
How much energy is consumed when a current of 5 ampere flows through the filament of a heater having resistance of 100 ohms for two hours? Express it in joules.
How much energy is consumed when a current of 5 ampere flows through the filament of a heater having resistance of 100 ohms for two hours? Express it in joules.