Answer:
d) one-fourth is the correct answer.
We know
p=v²/R
where R is constant
p turns 1/4 times when V is halved
The electric power is one-fourth of the actual value when the potential difference between the ends of a fixed resistor is halved.
If the potential difference between the ends of a fixed resistor is halved, the electric power will becomes: a) double b) half c) four times d) one-fourth
If the potential difference between the ends of a fixed resistor is halved, the electric power will becomes: a) double b) half c) four times d) one-fourth