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In all the following systems of equations determine whether the system has a unique solution, no solution or infinite solutions. If In case there is a unique solutionx-3y-3=0, 3x-9y-2=0
CBSE | Class 10 | Exercise 3.5 | Maths | Pair of Linear Equations In Two Variables | RD Sharma
In all the following systems of equations determine whether the system has a unique solution, no solution or infinite solutions. If In case there is a unique solutionx-3y-3=0, 3x-9y-2=0

Given system of equations is:

x-3y-3=0

3x-9y-2=0

Above equations are in the form of

{{a}_{1}}x+{{b}_{1}}y-{{c}_{1}}=0

{{a}_{2}}x+{{b}_{2}}y-{{c}_{2}}=0

Here, {{a}_{1}}=1,{{b}_{1}}=-3,{{c}_{1}}=-3

{{a}_{2}}=3,{{b}_{2}}=-9,{{c}_{2}}=-2

So according to the question, we get

{{a}_{1}}/{{a}_{2}}=1/3

{{b}_{1}}/{{b}_{2}}=-3/-9=1/3

{{c}_{1}}/{{c}_{2}}=-3/-2=3/2

{{a}_{1}}/{{a}_{2}}={{b}_{1}}/{{b}_{2}}\ne {{c}_{1}}/{{c}_{2}}

Therefore, we can conclude that, given system of equation has no solution.

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