(i) quadrant OACB,

(ii) shaded region.

Solution:

Quadrants’ radius = 3.5 cm or 7/2 cm

(i) The area of the quadrant OACB = (πR²)/4 cm²

= (22/7)×(7/2)×(7/2)/4 cm²

= 77/8 cm²

(ii) The area of triangle BOD = (½)×(7/2)×2 cm²

= 7/2 cm²

Area of quadrant – Area of triangle BOD = Area of shaded region

= (77/8)-(7/2) cm² = 49/8 cm²

= 6.125 cm²