In the given figure, O is the point inside a ∆MNP such that ∆MOP = ${90^0}$.OM = 16 cm and OP = 12 cm if MN = 21cm and ∆NMP = ${90^0}$ then NP=?

Home » In the given figure, O is the point inside a ∆MNP such that ∆MOP = .OM = 16 cm and OP = 12 cm if MN = 21cm and ∆NMP = then NP=?

In the given figure, O is the point inside a ∆MNP such that ∆MOP = ${90^0}$ .OM = 16 cm and OP = 12 cm if MN = 21cm and ∆NMP = ${90^0}$ then NP=?

In the given figure, O is the point inside a ∆MNP such that ∆MOP = ${90^0}$ .OM = 16 cm and OP = 12 cm if MN = 21cm and ∆NMP = ${90^0}$ then NP=?

Answer:

In right triangle MOP,

By using Pythagoras theorem,

????????² = ????????² + ????????²

=> 12² + 16²

=> 144 + 256

=> 400

MO = 20 cm

In right triangle MPN,

By using Pythagoras theorem,

????????² = ????????² + ????????²

=> 21² + 20²

=> 441 + 400

=> 841

MP = 29 cm

i

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