Jamila sold a table and a chair for ₹1050, thereby making a profit of 10\% on the table and 25\% on the chair. If she had taken a profit of 25\% on the table and 10\% on the chair she would have got ₹1065. Find the cost price of each.
Jamila sold a table and a chair for ₹1050, thereby making a profit of 10\% on the table and 25\% on the chair. If she had taken a profit of 25\% on the table and 10\% on the chair she would have got ₹1065. Find the cost price of each.

Let the cost price of one table and one chair be ₹ a and ₹ b, respectively.

The selling price of the table, when it’s sold at a profit of 10\%=₹a+10a/100=₹110a/100

The selling price of the chair, when it’s sold at a profit of 25\%=₹b+25b/100=₹125b/100

According to the question

110a/100+125b/100=1050… (a)

Similar,

The selling price of the table, when it’s sold at a profit of 25\%=₹(a+25a/100)=₹125a/100

The selling price of the chair, when it’s sold at a profit of 10\%=₹(b+10b/100)=₹110b/100

Therefore, again from the question

125a/100+110b/100=1065… (b)

Re- written (a) and (b) with their simplest coefficients,

11a/10+5b/4=1050…….. (c)

5a/4+11b/10=1065….. (d)

Adding (c) and (d), we get

(11/10+5/4)a+(5/4+11/10)b 2115

47/20a+47/20b=2115

a+b=2115(20/47)=900

a=900-b ……. (e)

Using (e) in (c),

11(900-b)/10+5b/4=1050

2\left( 9900-11b \right)+25b=1050\times 20[After taking LCM]

19800-22b+25b=21000

3b=1200

b=400

Putting b=400 in (e),

a=900-400=500

Therefore, the cost price of the table is ₹500 and that of the chair is ₹400.