Answer:
Given in question :
Potential difference = constant
Also, we know that,
V = IR
I = V/R
Given that V is constant, therefore, I will be proportional to 1/R.
Therefore, when R is halved, I also becomes double.
Q8. Keeping the potential difference constant, the resistance of a circuit is halved. By how much does the current change?
Q8. Keeping the potential difference constant, the resistance of a circuit is halved. By how much does the current change?