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Home » M2O is the oxide of metal “M” which is above hydrogen in the activity series. M2O, when dissolved in water, forms the corresponding hydroxide which is a good conductor of electricity. a. State the reaction taking place at the cathode. b. Name the product at the anode.
M2O is the oxide of metal “M” which is above hydrogen in the activity series. M2O, when dissolved in water, forms the corresponding hydroxide which is a good conductor of electricity.
a. State the reaction taking place at the cathode.
b. Name the product at the anode.
Chemistry | Class 10 | Electrolysis | ICSE | Selina
M2O is the oxide of metal “M” which is above hydrogen in the activity series. M2O, when dissolved in water, forms the corresponding hydroxide which is a good conductor of electricity.
a. State the reaction taking place at the cathode.
b. Name the product at the anode.

Solution:

Answer:

i)M+ + 1e– → M

ii) Oxygen gas is produced at the anode.

Explanation:

i) The activity series gives us a metal oxide M2O of metal ‘M’.
 M2O dissolves in water to generate hydroxide (H2O). M2O+H2OMOH

Metal ‘M’ hydroxide (MOH).
We all know metals lose electrons easily. Knowing that the valency of O is -2 and the metal ‘M’ is +1 in the given oxide M2O, Metal ‘M’ thus has one electron in its valence shell. So it loses an electron.

The process illustrated occurs at the cathode because reduction occurs there.

(ii) If metal ‘M’ is reduced, the oxygen atom is oxidized. The anode oxidizes. So the anode’s product is oxygen.

i

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