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Home » Primary alkyl halide C4H9Br (a) reacted with alcoholic KOH to give compound (b). Compound (b) is reacted with HBr to give (c) which is an isomer of (a). When (a) is reacted with sodium metal it gives compound (d), C8H18 which is different from the compound formed when n-butyl bromide is reacted with sodium. Give the structural formula of (a) and write the equations for all the reactions.
Primary alkyl halide C4H9Br (a) reacted with alcoholic KOH to give compound (b). Compound (b) is reacted with HBr to give (c) which is an isomer of (a). When (a) is reacted with sodium metal it gives compound (d), C8H18 which is different from the compound formed when n-butyl bromide is reacted with sodium. Give the structural formula of (a) and write the equations for all the reactions.
CBSE | Chemistry | Class 12 | Haloalkanes and Haloarenes | NCERT
Primary alkyl halide C4H9Br (a) reacted with alcoholic KOH to give compound (b). Compound (b) is reacted with HBr to give (c) which is an isomer of (a). When (a) is reacted with sodium metal it gives compound (d), C8H18 which is different from the compound formed when n-butyl bromide is reacted with sodium. Give the structural formula of (a) and write the equations for all the reactions.

The formula C4H9Br is used to make two main alkyl halides. They’re n-butyl bromide and isobutyl bromide, respectively.

Compound (a) is therefore either nbutyl bromide or isobutyl bromide. Compound (a) now combines with Na metal to generate molecule (b), which has the molecular formula C8H18 and is distinct from the compound formed when nbutyl bromide reacts with Na metal. Isobutyl bromide must therefore be compound (a).

2, 5dimethylhexane is thus compound (d).

Compound (a) interacts with alcoholic KOH to produce compound (b) (b). Compound (b) is thus 2methylpropene.

Compound (b) also interacts with HBr to form compound (c), which is an isomer of compound (b) (a). Compound (c) is thus 2-Bromo-2-methylpropane.

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