Prove that the Greatest Integer Function f : R → R, given by f(x) = [x], is neither one- one nor onto, where [x] denotes the greatest integer less than or equal to x.
Prove that the Greatest Integer Function f : R → R, given by f(x) = [x], is neither one- one nor onto, where [x] denotes the greatest integer less than or equal to x.

Solution:

Capacity f : R → R, given by f(x) = [x] f(x) = 1, since 1 ≤ x ≤ 2

f(1.2) = [1.2] = 1

f(1.9) = [1.9] = 1

Yet, 1.2 ≠ 1.9

f isn’t one-one.

There is no division appropriate or inappropriate having a place with co-space of f has any pre-picture in its area.

For instance, f(x) = [x] is consistently a number

for 0.7 has a place with R there doesn’t exist any x in space R where f(x) = 0.7 f isn’t onto.

Subsequently demonstrated, the Greatest Integer Function is neither one-one nor onto.