Ramesh travels 760km to his home partly by train and partly by car. It takes 8hr if he travels 160km by train and the rest by car. He takes 12min more if he travels 240km by train and the rest by car. Find the speed of the train and car respectively.
Ramesh travels 760km to his home partly by train and partly by car. It takes 8hr if he travels 160km by train and the rest by car. He takes 12min more if he travels 240km by train and the rest by car. Find the speed of the train and car respectively.

Let’s assume,

The speed of the train be Ckm/hr

The speed of the car =Dkm/hr

From the question, it’s understood that there are two parts

# Part 1: When Ramesh travels 160Km by train and the rest by car.

# Part 2: When Ramesh travels 240Km by train and the rest by car.

Part 1,

Time taken by Ramesh to travel 160km by train =160/Chrs [∵ time = distance/ speed]

Time taken by Ramesh to travel the remaining (760-160)km i.e., 600km by car =600/Dhr

So, the total time taken by Ramesh to cover 760Km=160/Chrs+600/Dhr

It’s given that,

Total time taken for this journey =8hr

So, by equations its

160/C+600/D=8

20/C+75/D=1 [on dividing previous equation by 8] …………………… (i)

Part 2,

Time taken by Ramesh to travel 240km CD train =240/Chrs

Time taken by Ramesh to travel (760-240)=520km CD car=520/Dhr

For this journey, it’s given that Ramesh will take a total of 8 hours and 12 minutes to finish.

240/C+520/D=8hrs12mins=8+(12/60)=41/5hr

240/C+520/D=41/5

6/C+13/D=41/200 ………. (ii)

Solving (i) and (ii), we get the required solution

Let’s take 1/C=u and 1/D=v,

So, (i) and (ii) becomes,

20u+75v=1 ……….. (iii)

6u+13v=41/200 ……. (iv)

On multiplying (iii) by 3 and (iv) by 10,

60u+225v=3

60u+130v=41/20

Subtracting the above two equations, we get

(225-130)v=3-41/20

95v=19/20

v=19/\left( 20\times 95 \right)=1/100

D=1/v=100

Using v=1/100 in (iii) to find v,

20u+75(1/100)=1

20u=1-75/100

20u=25/100=1/4

u=1/80

C=1/u=80

So, the speed of the train is 80km/hr and the speed of the car is 100km/hr.