Solve: -4x > 30, when (i) x ∈ R (ii) x ∈ Z
Solve: -4x > 30, when (i) x ∈ R (ii) x ∈ Z

-4x > 30

dividing by 4, we get

    \[\begin{array}{*{35}{l}} -4x/4\text{ }>\text{ }30/4  \\ -x\text{ }>\text{ }15/2  \\ x\text{ }<\text{ }\text{ }-15/2  \\ \end{array}\]

(i) x ∈ R

When x is a real number, the solution of the given inequation is (-∞, -15/2).

(ii) x ∈ Z

When, -8 < -15/2 < -7

So when,  x is an integer, the maximum possible value of x is -8.

The solution of the given inequation is {…, –11, –10, -9, -8}.