Now, let’s multiply LHS and RHS by for both (i) and (ii) for making integral coefficients and constants.
(i) ⇒
……………………….. (iii)
(ii) ⇒
…………………………… (iv)
From (iii)
……………………………… (v)
Now, substituting A in equation (iv) we get,
⇒ [After taking LCM]
⇒
⇒
Now, by putting the value of B in the equation (v), we get
⇒
⇒
∴
Thus, the value of A and B so obtained are and respectively.