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Solve the following two variable Linear equation A+B/2=4, 2B+A/3=5
CBSE | Class 10 | Exercise 3.3 | Maths | Pair of Linear Equations In Two Variables | RD Sharma
Solve the following two variable Linear equation A+B/2=4, 2B+A/3=5

The given pair of equations are:

A+B/2=4 ……………………. (i)

2B+A/3=5……………………. (ii)

From (i) we get,

A+B/2=4

⇒ 2A+B=8 [After taking LCM]

⇒ B=8-2A …..(iv)

From (ii) we get,

A+6B=15 ……………… (iii) [After taking LCM]

Substituting B in (iii), we get

A+6(8-2A)=15

⇒ A+48-12A=15

⇒ -11A=15-48

⇒ -11A=-33

⇒ A=3

Putting A=3 in (iv), we get

B=8-\left( 2\times 3 \right)

∴ B=8-6=2

Hence, the solution of the given system of equation are A=3 and B=2 respectively.

i

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