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Home » The areas of two similar triangles are 169cm2 and 121cm2 respectively. If the longest side of the larger triangle is 26cm, find the longest side of the smaller triangle.
The areas of two similar triangles are 169cm2 and 121cm2 respectively. If the longest side of the larger triangle is 26cm, find the longest side of the smaller triangle.
CBSE | Class 10 | Exercise 4C | Maths | RS Aggarwal | Triangles
The areas of two similar triangles are 169cm2 and 121cm2 respectively. If the longest side of the larger triangle is 26cm, find the longest side of the smaller triangle.

Answer:

Given,

Triangles are similar.

The ratio of the areas of these triangles will be equal to the ratio of squares of their corresponding sides.

Let the longest side of smaller triangle be X cm.

???????? (???????????????????????? ????????????????????????????????) / ???????? (???????????????????????????? ????????????????????????????????) = (???????????????????????????? ???????????????? ???????? ???????????????????????? ????????????????????????le)2 / (???????????????????????????? ???????????????? ???????? ???????????????????????????? ????????????????????????????????)2

\frac{169}{121}=\frac{26^{2}}{x^{2}}

x=\sqrt{\frac{26 \times 26 \times 121}{169}}

x=22

The longest side of the smaller triangle is 22 cm.

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