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Home » The oxide that gives H2O2 on treatment with dilute H2SO4 is — (i) PbO2 (ii) BaO2 .8H2O + O2 (iii) MnO2 (iv) TiO2
The oxide that gives H2O2 on treatment with dilute H2SO4 is — (i) PbO2 (ii) BaO2 .8H2O + O2 (iii) MnO2 (iv) TiO2
CBSE | Chemistry | Class 11 | Hydrogen | NCERT
The oxide that gives H2O2 on treatment with dilute H2SO4 is — (i) PbO2 (ii) BaO2 .8H2O + O2 (iii) MnO2 (iv) TiO2

Solution:

Option (ii) is the answer.

The oxide that gives H _{2} O _{2} on treatment with dilute H _{2} SO _{4} is BaO _{2} \cdot 8 H _{2} O.
BaO2·8H2O(s)+H2SO4(aq)→BaSO4(s)+H2O2(aq)+8H2O(l)BaO _{2} \cdot 8 H _{2} O ( s )+ H _{2} SO _{4}( aq ) \rightarrow BaSO _{4}( s )+ H _{2} O _{2}( aq )+8 H _{2} O ( l )

i

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