Answer –

We are given,

The EMF of the battery, E = 12 V

The internal resistance of the batter, R = 0.4 Ω

The amount of maximum current drawn from the battery  = I

We know that, according to Ohm’s law,

E = IR

Upon rearranging, we get –

I = E/R

Upon substituting values in above equation, we get

Hence, the maximum current drawn from the given battery is 30 A.