The torque (\vec{\tau}) experienced by a current-loop of magnetic moment (\vec{M}) placed in magnetic field \vec{B} is (a) \vec{\tau}=\vec{M} \times \vec{B} (b) \vec{\tau}=\vec{B} \times \vec{M} (C) \vec{\tau}=\frac{\vec{M}}{\vec{B}} (d) \vec{\tau}=\vec{M} \vec{B}
The torque (\vec{\tau}) experienced by a current-loop of magnetic moment (\vec{M}) placed in magnetic field \vec{B} is (a) \vec{\tau}=\vec{M} \times \vec{B} (b) \vec{\tau}=\vec{B} \times \vec{M} (C) \vec{\tau}=\frac{\vec{M}}{\vec{B}} (d) \vec{\tau}=\vec{M} \vec{B}

Answer: Option (a)\vec{\tau}=\vec{M} \times \vec{B}