The treatment of alkyl chlorides with aqueous KOH leads to the formation of alcohols but in the presence of alcoholic KOH, alkenes are major products. Explain.
The treatment of alkyl chlorides with aqueous KOH leads to the formation of alcohols but in the presence of alcoholic KOH, alkenes are major products. Explain.

KOH almost entirely ionizes in an aqueous solution, yielding OH ions. Because the OH ion is a powerful nucleophile, it causes the alkyl chloride to undergo a substitution reaction, resulting in the formation of alcohol.

An alcoholic solution of KOH, on the other hand, contains the alkoxide (RO) ion, which is a strong base. By removing a molecule of HCl, it can extract hydrogen from the -carbon of the alkyl chloride and generate an alkene.