To divide a line segment \[\mathbf{AB}\]in the ratio\[\mathbf{4}:\mathbf{7}\], a ray \[\mathbf{AX}\]is drawn first such that \[\mathbf{BAX}\]is an acute angle and then points \[{{\mathbf{A}}_{\mathbf{1}}},\text{ }{{\mathbf{A}}_{\mathbf{2}}},\text{ }{{\mathbf{A}}_{\mathbf{3}}},\ldots .\]are located at equal distances on the ray \[\mathbf{AX}\]and the point \[\mathbf{B}\]is joined to \[\left( \mathbf{A} \right)\text{ }{{\mathbf{A}}_{\mathbf{12}}}~\left( \mathbf{B} \right)\text{ }{{\mathbf{A}}_{\mathbf{11}}}~\left( \mathbf{C} \right)\text{ }{{\mathbf{A}}_{\mathbf{10}}}~\left( \mathbf{D} \right)\text{ }{{\mathbf{A}}_{\mathbf{9}}}\]

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To divide a line segment

$\mathbf{AB}$

in the ratio

$\mathbf{4}:\mathbf{7}$

, a ray

$\mathbf{AX}$

is drawn first such that

$\mathbf{BAX}$

is an acute angle and then points

${{\mathbf{A}}_{\mathbf{1}}},\text{ }{{\mathbf{A}}_{\mathbf{2}}},\text{ }{{\mathbf{A}}_{\mathbf{3}}},\ldots .$

are located at equal distances on the ray

$\mathbf{AX}$

and the point

$\mathbf{B}$

is joined to

$\left( \mathbf{A} \right)\text{ }{{\mathbf{A}}_{\mathbf{12}}}~\left( \mathbf{B} \right)\text{ }{{\mathbf{A}}_{\mathbf{11}}}~\left( \mathbf{C} \right)\text{ }{{\mathbf{A}}_{\mathbf{10}}}~\left( \mathbf{D} \right)\text{ }{{\mathbf{A}}_{\mathbf{9}}}$

CBSE | Class 10 | Exercise 10.1 | Maths | NCERT Exemplar

To divide a line segment

$\mathbf{AB}$

in the ratio

$\mathbf{4}:\mathbf{7}$

, a ray

$\mathbf{AX}$

is drawn first such that

$\mathbf{BAX}$

is an acute angle and then points

${{\mathbf{A}}_{\mathbf{1}}},\text{ }{{\mathbf{A}}_{\mathbf{2}}},\text{ }{{\mathbf{A}}_{\mathbf{3}}},\ldots .$

are located at equal distances on the ray

$\mathbf{AX}$

and the point

$\mathbf{B}$

is joined to

$\left( \mathbf{A} \right)\text{ }{{\mathbf{A}}_{\mathbf{12}}}~\left( \mathbf{B} \right)\text{ }{{\mathbf{A}}_{\mathbf{11}}}~\left( \mathbf{C} \right)\text{ }{{\mathbf{A}}_{\mathbf{10}}}~\left( \mathbf{D} \right)\text{ }{{\mathbf{A}}_{\mathbf{9}}}$

SOLUTION:-

$\left( \mathbf{B} \right)\text{ }{{\mathbf{A}}_{\mathbf{11}}}$