Exercise 10.1 Archives - Noon Academy

Exercise 10.1

To divide a line segment
$\mathbf{AB}$
in the ratio
$\mathbf{5}\text{ }:\text{ }\mathbf{6}$
, draw a ray
$\mathbf{AX}$
such that
$\angle \mathbf{BAX}$
is an acute angle, then draw a ray
$\mathbf{BY}$
parallel to
$\mathbf{AX}$
and the points
${{\mathbf{A}}_{\mathbf{1}}},\text{ }{{\mathbf{A}}_{\mathbf{2}}},\text{ }{{\mathbf{A}}_{\mathbf{3}}},\text{ }\ldots$
and
${{\mathbf{B}}_{\mathbf{1}}},\text{ }{{\mathbf{B}}_{\mathbf{2}}},\text{ }{{\mathbf{B}}_{\mathbf{3}}},\text{ }\ldots$
are located at equal distances on ray
$\mathbf{AX}$
and
$\mathbf{BY}$
, respectively. Then the points joined are
$\left( \mathbf{A} \right)\text{ }{{\mathbf{A}}_{\mathbf{5}}}~\mathbf{and}\text{ }{{\mathbf{B}}_{\mathbf{6}}}~$

$\left( \mathbf{B} \right)\text{ }{{\mathbf{A}}_{\mathbf{6}}}~\mathbf{and}\text{ }{{\mathbf{B}}_{\mathbf{5}}}~$

$~\left( \mathbf{C} \right)\text{ }{{\mathbf{A}}_{\mathbf{4}}}~\mathbf{and}\text{ }{{\mathbf{B}}_{\mathbf{5}}}$

$\left( \mathbf{D} \right)\text{ }{{\mathbf{A}}_{\mathbf{5}}}~\mathbf{and}\text{ }{{\mathbf{B}}_{\mathbf{4}}}$

CBSE, Class 10, Exercise 10.1, Maths, NCERT Exemplar

\[\left( \mathbf{A} \right)\text{ }{{\mathbf{A}}_{\mathbf{5}}}~\mathbf{and}\text{ }{{\mathbf{B}}_{\mathbf{6}}}\] As per the inquiry, A line portion \[AB\]in the proportion \[5:7\] Along these...

To divide a line segment
$\mathbf{AB}$
in the ratio
$\mathbf{4}:\mathbf{7}$
, a ray
$\mathbf{AX}$
is drawn first such that
$\mathbf{BAX}$
is an acute angle and then points
${{\mathbf{A}}_{\mathbf{1}}},\text{ }{{\mathbf{A}}_{\mathbf{2}}},\text{ }{{\mathbf{A}}_{\mathbf{3}}},\ldots .$
are located at equal distances on the ray
$\mathbf{AX}$
and the point
$\mathbf{B}$
is joined to
$\left( \mathbf{A} \right)\text{ }{{\mathbf{A}}_{\mathbf{12}}}~\left( \mathbf{B} \right)\text{ }{{\mathbf{A}}_{\mathbf{11}}}~\left( \mathbf{C} \right)\text{ }{{\mathbf{A}}_{\mathbf{10}}}~\left( \mathbf{D} \right)\text{ }{{\mathbf{A}}_{\mathbf{9}}}$

CBSE, Class 10, Exercise 10.1, Maths, NCERT Exemplar

SOLUTION:- \[\left( \mathbf{B} \right)\text{ }{{\mathbf{A}}_{\mathbf{11}}}\] As per the inquiry, A line section\[~AB\] in the proportion \[4:7\] Thus, \[A:B\text{ }=\text{ }4:7\] Presently, Draw a...

To divide a line segment
$\mathbf{AB}$
in the ratio
$\mathbf{5}:\mathbf{7}$
, first a ray
$\mathbf{AX}$
is drawn so that
$\mathbf{BAX}$
is an acute angle and then at equal distances points are marked on the ray
$\mathbf{AX}$
such that the minimum number of these points is (A)
$\mathbf{8}$
(B)
$\mathbf{10}$
(C)
$~\mathbf{11}$
(D)
$\mathbf{12}$

CBSE, Class 10, Exercise 10.1, Maths, NCERT Exemplar

SOLUTION:- \[\left( D \right)\text{ }12\] As indicated by the inquiry, A line fragment \[AB\]in the proportion \[5:7\] In this way, \[A:B\text{ }=\text{ }5:7\] Presently, Draw a beam \[AX\]making an...