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Home » Two vessels separately contain two ideal gases and at the same temperature, the pressure of a being twice that of . Under such conditions, the density of is found to be times the density if . The ratio of molecular weight of and is: (1) (2) (3) (4) 2
Two vessels separately contain two ideal gases A and B at the same temperature, the pressure of a being twice that of B. Under such conditions, the density of \mathrm{A} is found to be 1.5 times the density if \mathrm{B}. The ratio of molecular weight of \mathrm{A} and \mathrm{B} is: (1) \frac{1}{2} (2) \frac{2}{3} (3) \frac{3}{4} (4) 2
Physics | Physics
Two vessels separately contain two ideal gases A and B at the same temperature, the pressure of a being twice that of B. Under such conditions, the density of \mathrm{A} is found to be 1.5 times the density if \mathrm{B}. The ratio of molecular weight of \mathrm{A} and \mathrm{B} is: (1) \frac{1}{2} (2) \frac{2}{3} (3) \frac{3}{4} (4) 2

The Solution is (3)
P_{A}=\frac{\rho_{A} M_{A}}{R T}, P_{B}=\frac{\rho_{B} M_{B}}{R T}=\frac{3}{2} \Rightarrow \frac{P_{A}}{P_{B}}=\frac{\rho_{A}}{\rho_{B}} \frac{M_{A}}{M_{B}}=2 \frac{M_{A}}{M_{B}}=\frac{3}{2}
So, \frac{M_{A}}{M_{M}}=\frac{3}{4}

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