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Home » What will be the tension of the vaporous blend when 0.5 L of H2 at 0.8 bar and 2.0 L of dioxygen at 0.7 bar are presented in a 1L vessel at 27°C?
What will be the tension of the vaporous blend when 0.5 L of H2 at 0.8 bar and 2.0 L of dioxygen at 0.7 bar are presented in a 1L vessel at 27°C?
CBSE | Chemistry | Class 11 | Exercise 1 | NCERT | States of Matter
What will be the tension of the vaporous blend when 0.5 L of H2 at 0.8 bar and 2.0 L of dioxygen at 0.7 bar are presented in a 1L vessel at 27°C?

Solution:

From the situation

    \[Pv\text{ }=\text{ }n\text{ }RT\]

for the two gases. We can compose

 

    \[\begin{array}{*{35}{l}} 0.8\text{ }x\text{ }0.5\text{ }=\text{ }nH2~x\text{ }RT~\text{ }or\text{ }nH2~~=\text{ }0.8\text{ }x\text{ }0.5/RT \\ ~ \\ ALSO~\text{ }0.7\text{ }x\text{ }2.0~\text{ }=\text{ }n02~.\text{ }RT~\text{ }or\text{ }n02~~=\text{ }0.7\text{ }x\text{ }2/RT \\ \end{array}\]

At the point when presented in 1 L vessel, then, at that point,

 

    \[Px1L\text{ }=\text{ }\left( n02~+\text{ }nH2 \right)~\text{ }RT\]

Putting the qualities, we get

 

    \[P\text{ }=\text{ }0.4\text{ }+\text{ }1.4\text{ }=\text{ }1.8\text{ }bar\]

Subsequently, the complete strain of the vaporous combination in the vessel is 1.8 bar

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