(i) a = 4, d = – 3
(ii) a = -1 d = 1/2
Solution(i):
Assume that the Arithmetic Progression series is a1, a2, a3, a4, a5 …
a1 = a = 4
a2 = a1+d = 4-3 = 1
a3 = a2+d = 1-3 = – 2
a4 = a3+d = -2-3 = – 5
As a result, the A.P. series will continue to be 4, 1, – 2 – 5 …
And, therefore the first four terms of this A.P. will be 4, 1, – 2 and – 5.
Solution(ii):
Assume that the Arithmetic Progression series is a1, a2, a3, a4, a5 …
a2 = a1+d = -1+1/2 = -1/2
a3 = a2+d = -1/2+1/2 = 0
a4 = a3+d = 0+1/2 = 1/2
As a result, the A.P. series will continue to be -1, -1/2, 0, 1/2
And, therefore the first four terms of this A.P. will be -1, -1/2, 0 and 1/2.