Let AD to be the height of the man, AD = 2 m.
(i) In ∆CED,
And, as AB = DE we get,
AB = 20 m
(ii) Let A’D’ be the new position of the man and θ be the angle of elevation of the top of the tower.
So, D’E = 15 m
In ∆CED,
Let AD to be the height of the man, AD = 2 m.
(i) In ∆CED,
And, as AB = DE we get,
AB = 20 m
(ii) Let A’D’ be the new position of the man and θ be the angle of elevation of the top of the tower.
So, D’E = 15 m
In ∆CED,