(a) ₹ 
at 
p.a. in 
years.
Solution:-
Principal = P
Rate = R
Time = T
Given :
Principal, P = ₹ , Rate, r = 
Time, t = 3 years
For the first year, t = 
year
S.I. = (P × r × t)/
= 
.
= ₹ 
A = P + S.I.
= 
= ₹ 
New principal is ₹ 8,400.
For the second year, t = year, p = ₹
S.I. = (P × r × t)/
= 
= ₹ 
A = P + S.I.
= 
= ₹ 
New principal is ₹ .
For the Third year, t = year, p = ₹
S.I. = (P × r × t)/
= 
= ₹ 
A = P + S.I.
= 
= ₹ 
C.I. = Interest in first year + interest in second year + interest in third year
= ₹ 
= ₹ 
Solution:-
P = ₹ 
, r = 
, t = 
years
For the first year, t = year
S.I. = (P × r × t)/
= 
= ₹ 
A = P + S.I.
= 
= ₹ 
New principal is ₹ .
For the second year, t = year, p = ₹
S.I. = (P × r × t)/
= = 
= ₹ 
A = P + S.I.
= 
= ₹ 
C.I. = Interest in first year + interest in second year
= ₹ 
= ₹ 
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(b) ![\left[\mathrm{Pd}(\mathrm{CN})_{4}\right]^{2-}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-ffda616d3dbe7dc8925722e87005924e_l3.png "Rendered by QuickLaTeX.com")
(c) ![\left[\mathrm{PdCl}_{4}\right]^{2-}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-90cc6a4f4d42dee46e06d6f8ed516b7a_l3.png "Rendered by QuickLaTeX.com")
(d) ![\left[\mathrm{NiCl}_{4}\right]^{2}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-149ee5c95bd9cfcc4405704fba2e1bab_l3.png "Rendered by QuickLaTeX.com")
(d) all of these