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Home » The 7th term of an A.P. is and its term is Find the A.P. An arithmetic progression or arithmetic sequence is a number’s sequence such that the difference between the consecutive terms is constant.
The 7th term of an A.P. is 32 and its {{13}^{th}} term is 62. Find the A.P. An arithmetic progression or arithmetic sequence is a number’s sequence such that the difference between the consecutive terms is constant.
Arithmetic Progression | Class 10 | ICSE | Maths | RD Sharma
The 7th term of an A.P. is 32 and its {{13}^{th}} term is 62. Find the A.P. An arithmetic progression or arithmetic sequence is a number’s sequence such that the difference between the consecutive terms is constant.

Solution:

Given,

{{a}_{7}}=32 and {{a}_{13}}=62

From {{a}_{n}}-{{a}_{k}}=\left( a+nd-d \right)-\left( a+kd-d \right)

=\left( n-k \right)d

where n and k represents the nth and kth terms of an A.P

{{a}_{13}}-{{a}_{7}}=\left( 13-7 \right)d=62-32=30

6d=30

d=5

Now,

{{a}_{7}}=a+\left( 7-1 \right)5=32

a+30=32

a=2

Hence, the A.P is 2,7,12,17, ……

i

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