According to the question,
battery emf V = 15 V
RB = 2 ohm (Internal resistance of battery)
Resistances given in circuit are 4 ohm and 6 ohm respectively.
(i) In series,
Equivalent resistance, R = 12 ohm
Current I = 15 / 12
I = 1.25 A
Voltage across resistor
, V2 = IR = 1.25 × 6
V2 = 7.50 V
Time, t = 1 min = 60 sec
Energy across R2, E = V2t / R
E = [(7.5)2 × 60] / 6
Hence,
E = 562.5 J
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(b) ![\left[\mathrm{Pd}(\mathrm{CN})_{4}\right]^{2-}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-ffda616d3dbe7dc8925722e87005924e_l3.png "Rendered by QuickLaTeX.com")
(c) ![\left[\mathrm{PdCl}_{4}\right]^{2-}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-90cc6a4f4d42dee46e06d6f8ed516b7a_l3.png "Rendered by QuickLaTeX.com")
(d) ![\left[\mathrm{NiCl}_{4}\right]^{2}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-149ee5c95bd9cfcc4405704fba2e1bab_l3.png "Rendered by QuickLaTeX.com")
(d) all of these