According to the question,
ε = 3 volt
I = 1.5 A
V = 2.7 V
V = ε – Ir
r = (e – V) / I
r = (3 – 2.7) / 1.5
Therefore,
r = 0.2 ohm
According to the question,
ε = 3 volt
I = 1.5 A
V = 2.7 V
V = ε – Ir
r = (e – V) / I
r = (3 – 2.7) / 1.5
Therefore,
r = 0.2 ohm