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A die is thrown, find the probability of following events: (v) A number less than 6 will appear.
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A die is thrown, find the probability of following events: (v) A number less than 6 will appear.

The possible outcomes when a die is thrown are 1, 2, 3, 4, 5 and 6.

Then the sample space is, S{\text{ }} = {\text{ }}\left\{ {1,{\text{ }}2,{\text{ }}3,{\text{ }}4,{\text{ }}5,{\text{ }}6} \right\}

n\left( S \right){\text{ }} = {\text{ }}6

(v) A number less than 6 will appear.

Suppose E be the event of getting a number less than 6, then

E = {\text{ }}\left( {1,{\text{ }}2,{\text{ }}3,{\text{ }}4,{\text{ }}5} \right)

So, n{\text{ }}\left( E \right){\text{ }} = {\text{ }}5

P\left( {Event} \right) = \frac{{Number{\text{ }}of{\text{ }}outcomes{\text{ }}favorable{\text{ }}to{\text{ }}event}}{{Total{\text{ }}number{\text{ }}of{\text{ }}possible{\text{ }}outcomes}}

P(E) = \frac{{n(E)}}{{n(S)}}

Therefore, P(E) = \frac{5}{6}.

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