A die is thrown once. Find the probability of getting a number: (iii) less than 8 (iv) greater than 6
A die is thrown once. Find the probability of getting a number: (iii) less than 8 (iv) greater than 6

(iii) On a dice, numbers less than 8 = {1, 2, 3, 4, 5, 6}

So, n(E) = 6

Hence, probability of getting a number less than 8 = n(E)/ n(S) = 6/6 = 1

(iv) On a dice, numbers greater than 6 = 0

So, n(E) = 0

Hence, probability of getting a number greater than 6 = n(E)/ n(S) = 0/6 = 0