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Home » Among and species, the hybridisation state of atoms are respectively: A B C D dsp
Among [\mathrm{Ni}(\mathrm{CO}) 4],[\mathrm{Ni}(\mathrm{CN}) 4]^{2-} and \left[\mathrm{NiCl}_{4}\right]^{2-} species, the hybridisation state of \mathrm{Ni} atoms are respectively:
A \quad s p^{3}, d s^{2} p, d s p^{2}

B \mathrm{sp}^{3}, \mathrm{~d} \mathrm{sp}^{2}, \mathrm{sp}^{3}
C \mathrm{sp}^{3}, \mathrm{sp}^{3}, \mathrm{~d} \mathrm{sp}^{2}
D \quad dsp ^{2}, \mathrm{sp}^{3}, \mathrm{sp}^{3}
Chemistry | Previous Year Question Papers
Among [\mathrm{Ni}(\mathrm{CO}) 4],[\mathrm{Ni}(\mathrm{CN}) 4]^{2-} and \left[\mathrm{NiCl}_{4}\right]^{2-} species, the hybridisation state of \mathrm{Ni} atoms are respectively:
A \quad s p^{3}, d s^{2} p, d s p^{2}

B \mathrm{sp}^{3}, \mathrm{~d} \mathrm{sp}^{2}, \mathrm{sp}^{3}
C \mathrm{sp}^{3}, \mathrm{sp}^{3}, \mathrm{~d} \mathrm{sp}^{2}
D \quad dsp ^{2}, \mathrm{sp}^{3}, \mathrm{sp}^{3}

Correct option is
B \mathrm{sp}^{3}, \mathrm{dsp}^{2}, \mathrm{sp}^{3}
As CN ^{-}is a strong ligand so here pairing happens and dsp ^{2} hybridisation (square planar) takes place while [\mathrm{Ni}(\mathrm{CO}) 4] and [\mathrm{NiCl} 4]^{2-} have sp ^{3} hybridisation (tetrahedral shape).
Hence, the correct option is B.

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