The oxidation number of \mathrm{Ni} in \mathrm{Ni}(\mathrm{CO}) \& is +2.
A True
B False
C Anomalous
D None of these
The oxidation number of \mathrm{Ni} in \mathrm{Ni}(\mathrm{CO}) \& is +2.
A True
B False
C Anomalous
D None of these

Correct option is B False
Let x be the oxidation number of \mathrm{Ni} in \mathrm{Ni}(\mathrm{CO})_{4}.
Since the overall
charge on the complex is 0 , the sum of oxidation states of all elements in
it should be equal to 0 .
Therefore, x+4(0)=0
Hence, x=0
Thus, the oxidation number of \mathrm{Ni} in \mathrm{Ni}(\mathrm{CO})_{4} is 0 .
Hence, the correct option is B