Let’s the present ages of the father as a years and that of his son’s age as b years. According to the question,, The present age of father is three years more than three times the age of the son....
Ten years ago, the age of father was twelve times as old as his son and after ten years, the age of father will be twice as old as his son will be then. Now find the present ages.
Let’s the present ages of the father as a years and that of his son’s age as b years. According to the question,, After 10 years, the age of father will be $(a+10)$ years and son’s age will be...
After six year a man’s age will be three times the age of his son and three years ago, he was nine times as old as his son. Now find the present ages.
Let the present ages of the father as a years and that of his son’s age as b years. According to question After 6 years, the man’s age will be $(a+6)$ years and son’s age will be $(b+6)$ years. So,...
A is older to B by 2 years. The age of A father F is twice as old as A and B is twice as old as his sister S. If the age of the father and sister differ by 40 years, Now find the age of A.
Assuming that, the present age of $A=a$ The present age of $B=b$ The present age of $F=z$ The present age of $S=t$ Now from the questions A is elder to b by 2 years. ⇒ $a=b+2$ F is twice as old as...
After ten years, the age of A will be twice as old as B and five years ago, the age of A was three times as old as the age of B. Now find the present ages of A and B.
Let the present ages of A be a years and that of B be b years According to the question, After 10 years, A’s age will be $(a+10)$ years and B’s age will be $(b+10)$ years. Now, the relation between...
The age of the father is three times as old as his son. After the twelve years, the age of the father is twice as that of his son. Find their present ages.
Let’s assume the present ages of the father as a years and that of his son’s age as b years. From the question it’s given that, Father is 3 times as old as his son. (Present) So, the equation formed...