Excercise 9A Archives - Noon Academy

Excercise 9A

Evaluate:

CBSE, Class 11, Combinations, Excercise 9A, Maths, RS Aggarwal

90C88 Answer : We know that: ⇒90C88=4005 Ans: ⇒90C88=4005

Evaluate:

CBSE, Class 11, Combinations, Excercise 9A, Maths, RS Aggarwal

16c13 Answer : We know that: nCr = ⇒16C13= ⇒16C13= ⇒16C13 = ⇒16C13 = ⇒16C13 = ⇒16C13 =560 Ans: 16C13=560

Evaluate:

CBSE, Class 11, Combinations, Excercise 9A, Maths, RS Aggarwal

21C4 Answer : We know that: nCr ⇒20C4 ⇒20C4 ⇒20C4 ⇒20C4 ⇒20C4 ⇒20C4 =4845 Ans: 20C4 =4845

Prove that $f(x)=\left\{\begin{array}{c} \frac{x^{2}-x-6}{x-3}, \text { when } x \neq 3 \text { is continuous at } x=3 \\ 5, \text { when } x=3 \end{array}\right.$

CBSE, Class 12, Continuity and Differentiability, Excercise 9A, Maths, RS Aggarwal

Solution: Left Hand Limit: $\lim _{x \rightarrow 3-} f(x)=\lim _{x \rightarrow 3-} \frac{x^{2}-x-6}{x-3}$ $=\lim _{\mathrm{x} \rightarrow 3-} \frac{(\mathrm{x}+2)(\mathrm{x}-3)}{\mathrm{x}-3}$ [By...