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Home » During complete burning of one mole of butane, 2658 kJ of warmth is delivered. The thermochemical response for above change is    
During complete burning of one mole of butane, 2658 kJ of warmth is delivered. The thermochemical response for above change is

    \[\begin{array}{*{35}{l}} \left( I \right)\text{ }2C4H10\left( g \right)\text{ }+\text{ }13O2\left( g \right)\text{ }\to \text{ }8CO2\left( g \right)\text{ }+\text{ }10H2O\left( l \right)\text{ }cH\text{ }=\text{ }\text{ }2658.0\text{ }kJ\text{ }mol1 \\ ~ \\ \left( ii \right)\text{ }C4H10\left( g \right)\text{ }+13/2\text{ }O2\text{ }\left( g \right)\text{ }\to \text{ }4CO2\text{ }\left( g \right)\text{ }+\text{ }5H2O\text{ }\left( g \right)\text{ }cH\text{ }=\text{ }\text{ }1329.0\text{ }kJ\text{ }mol1 \\ ~ \\ \left( iii \right)\text{ }C4H10\left( g \right)\text{ }+13/2\text{ }O2\text{ }\left( g \right)\text{ }\to \text{ }4CO2\text{ }\left( g \right)\text{ }+\text{ }5H2O\text{ }\left( l \right)\text{ }cH\text{ }=\text{ }\text{ }2658.0\text{ }kJ\text{ }mol1 \\ ~ \\ \left( iv \right)\text{ }C4H10\text{ }\left( g \right)\text{ }+13/2\text{ }O2\text{ }\left( g \right)\text{ }\to \text{ }4CO2\text{ }\left( g \right)\text{ }+\text{ }5H2O\text{ }\left( l \right)\text{ }cH\text{ }=\text{ }+2658.0\text{ }kJ\text{ }mol1 \\ \end{array}\]

CBSE | Chemistry | Class 11 | Exercise 1 | NCERT Exemplar | Thermodynamics
During complete burning of one mole of butane, 2658 kJ of warmth is delivered. The thermochemical response for above change is

    \[\begin{array}{*{35}{l}} \left( I \right)\text{ }2C4H10\left( g \right)\text{ }+\text{ }13O2\left( g \right)\text{ }\to \text{ }8CO2\left( g \right)\text{ }+\text{ }10H2O\left( l \right)\text{ }cH\text{ }=\text{ }\text{ }2658.0\text{ }kJ\text{ }mol1 \\ ~ \\ \left( ii \right)\text{ }C4H10\left( g \right)\text{ }+13/2\text{ }O2\text{ }\left( g \right)\text{ }\to \text{ }4CO2\text{ }\left( g \right)\text{ }+\text{ }5H2O\text{ }\left( g \right)\text{ }cH\text{ }=\text{ }\text{ }1329.0\text{ }kJ\text{ }mol1 \\ ~ \\ \left( iii \right)\text{ }C4H10\left( g \right)\text{ }+13/2\text{ }O2\text{ }\left( g \right)\text{ }\to \text{ }4CO2\text{ }\left( g \right)\text{ }+\text{ }5H2O\text{ }\left( l \right)\text{ }cH\text{ }=\text{ }\text{ }2658.0\text{ }kJ\text{ }mol1 \\ ~ \\ \left( iv \right)\text{ }C4H10\text{ }\left( g \right)\text{ }+13/2\text{ }O2\text{ }\left( g \right)\text{ }\to \text{ }4CO2\text{ }\left( g \right)\text{ }+\text{ }5H2O\text{ }\left( l \right)\text{ }cH\text{ }=\text{ }+2658.0\text{ }kJ\text{ }mol1 \\ \end{array}\]

solution:

 

Choice (iii) is the appropriate response.

Exothermic reaction for combustion of one mole of butane is represented as

    \[\left( iii \right)\text{ }C4H10\left( g \right)\text{ }+13/2\text{ }O2\text{ }\left( g \right)\text{ }\to \text{ }4CO2\text{ }\left( g \right)\text{ }+\text{ }5H2O\text{ }\left( l \right)\text{ }cH\text{ }=\text{ }\text{ }2658.0\text{ }kJ\text{ }mol1\]

i

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