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Home » (a) Explain the following in terms of gain or loss of Oxygen with one example each: (i) Oxidation (ii) reduction (b) When copper powder is heated strongly in air, it forms copper oxide. Write a balanced chemical equation for this reaction. Name (i) substance oxidised, and (ii) substance reduced
(a) Explain the following in terms of gain or loss of Oxygen with one example each:
(i) Oxidation (ii) reduction
(b) When copper powder is heated strongly in air, it forms copper oxide. Write a balanced chemical equation for this reaction.
Name
(i) substance oxidised, and
(ii) substance reduced
CBSE | Chemical Reactions and Equations | Chemistry | Class 10 | Lakhmir Singh
(a) Explain the following in terms of gain or loss of Oxygen with one example each:
(i) Oxidation (ii) reduction
(b) When copper powder is heated strongly in air, it forms copper oxide. Write a balanced chemical equation for this reaction.
Name
(i) substance oxidised, and
(ii) substance reduced

(a) Oxidation is the addition of oxygen while reduction is the removal of oxygen.

H2S + Cl2→ S + 2HCl

In the reaction shown above, hydrogen is removed from hydrogen sulphide, so it is an oxidation reaction while hydrogen sulphide is oxidized to sulphur.

(b) 2Cu + O2 → 2Cu0

(i) Cu is oxidized (ii) O2is reduced

i

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