Equation of the curve is 
……….(i)
Slope of the tangent to the curve at the point (1, 2) to curve (i) is 
=1
Slope of the normal to the curve at (1, 2) is 
Equation of the normal to the curve (i) at (1, 2) is 
Find the equation of the normal to curve x^2 = 4y which passes through the point (1, 2).
Find the equation of the normal to curve x^2 = 4y which passes through the point (1, 2).