The two equal sides of an isosceles triangle with fixed base b are decreasing at the rate of 3 cm per second. How fast is the area decreasing when the two equal sides are equal to the base ?
The two equal sides of an isosceles triangle with fixed base b are decreasing at the rate of 3 cm per second. How fast is the area decreasing when the two equal sides are equal to the base ?

Let BC =  be the fixed base and AB = AC =  be

the two equal sides of given isosceles triangle.

Since  cm/s  ……….(i)

Area of  x BC x AM

 [By chain rule]

 cm2/s

Now when 

  cm2/s

Therefore, the area is decreasing at the rate of  cm2/s.