\sec ^{-1}\left(\frac{2}{\sqrt{3}}\right)y=\sec ^{-1}\left(\frac{2}{\sqrt{3}}\right)\sec y=2 / \sqrt{3}\sec y=\sec \frac{\pi}{6}
\sec ^{-1}
[0, \pi]
\sec ^{-1}\left(\frac{2}{\sqrt{3}}\right)\pi / 6$
Find the principal values of the following:\sec ^{-1}\left(\frac{2}{\sqrt{3}}\right)$
Find the principal values of the following:\sec ^{-1}\left(\frac{2}{\sqrt{3}}\right)$