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Given the standard electrode potentials, A g^{+} / A g=0.80 \mathrm{~V} \mathrm{Hg}^{2+} / \mathrm{Hg}=0.79 \mathrm{~V} \mathrm{Mg}^{2+} / \mathrm{Mg}=-2.37 \mathrm{~V} C r^{3+} / C r=-0.74 V Arrange these metals in their increasing order of reducing power.
CBSE | Chemistry | Class 11 | Exercise 1 | NCERT | Redox Reactions
Given the standard electrode potentials, A g^{+} / A g=0.80 \mathrm{~V} \mathrm{Hg}^{2+} / \mathrm{Hg}=0.79 \mathrm{~V} \mathrm{Mg}^{2+} / \mathrm{Mg}=-2.37 \mathrm{~V} C r^{3+} / C r=-0.74 V Arrange these metals in their increasing order of reducing power.

Solution:

The diminishing specialist is more grounded as the terminal potential declines. Subsequently, the expanding request of the lessening force of the given metals is as given underneath:

Ag < Hg < Cr < Mg < K

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