If \left[\begin{array}{ll}2 x-y & 5 \\ 3 & \mathrm{y}\end{array}\right]=\left[\begin{array}{ll}6 & 5 \\ 3 & -2\end{array}\right], then \mathbf{x}= (A) 3 (B) 4 (C) 5 (D) 8
If \left[\begin{array}{ll}2 x-y & 5 \\ 3 & \mathrm{y}\end{array}\right]=\left[\begin{array}{ll}6 & 5 \\ 3 & -2\end{array}\right], then \mathbf{x}= (A) 3 (B) 4 (C) 5 (D) 8

Sol.
Correct answer option is (none of these)