In the following reaction between lead sulphide and hydrogen peroxide:

    \[\mathbf{PbS}\left( \mathbf{s} \right)\text{ }+\text{ }\mathbf{4}{{\mathbf{H}}_{\mathbf{2}}}{{\mathbf{O}}_{\mathbf{2}}}\left( \mathbf{aq} \right)\text{ }\to \text{ }\mathbf{PbS}{{\mathbf{O}}_{\mathbf{4}}}\left( \mathbf{s} \right)\text{ }+\mathbf{4}{{\mathbf{H}}_{\mathbf{2}}}\mathbf{O}\left( \mathbf{l} \right)\]


(a) Which substance is reduced? (b) Which substance is oxidized?