Solve the following equations using graphical method: $a+b=4$ $2a–3b=3$ - Noon Academy

Solve the following equations using graphical method: $a+b=4$ $2a-3b=3$

Class 10 | Exercise 3.2 | Maths | Pair of Linear Equations In Two Variables | RD Sharma

Solve the following equations using graphical method: $a+b=4$ $2a-3b=3$

Given,

$a+b=4$ ……. (i)

$2a-3b=3$ ……. (ii)

From equation (i),

⇒ $b=(4-a)$

When $a=4$ , we get $b=(4-4)=0$

When $a=2$ , we get $b=(4-2)=2$

Thus, we have the following table giving Points on the line $a+b=4$

a	$4$	$2$
b	$0$	$2$

From equation (ii),

We solve for b:

⇒ $b=(2a-3)/3$

So, when $a=3$

$b=(2(3)-3)/3=1$

And, when $a=0$

⇒ $b=(2(0)-3)/3=-1$

Thus, we have the following table giving Points on the line $2a-3b=3$

a	$3$	$0$
b	$1$	$-1$

Graph of the equations (i) and (ii) is given below:

In given graph, the two lines intersect at a single Point P $(3,1)$

Thus, $a=3$ and $b=1$ .

i

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Question consists of two statements, namely, Assertion (A) and Reason (R). For selecting the correct answer, use the following code:

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